I\'m not sure how to even start this problem....assistance to answer the two que
ID: 1528329 • Letter: I
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I'm not sure how to even start this problem....assistance to answer the two questions on the page please!!! Much appreciated if you could explain what equations and numbers need to be used (show work) and not just give the answer.
Wednesday, February 1, 2017 ame SPRING 2017 Introductory Physics Stuntman Projectile Problem Due Monday, February 6 As a stunt driver, your job is to jump a car from building A to building B as shown. 1. What is the minimum velocity that you need leaving building A in order to land on the roof of building B? 2. Your car has a maximum acceleration of 3 m/s2. Starting from rest, what is the minimum distance from the edge of building A (dx) that you must have to reach the minimum velocity? Do all work on this page. (gnore any effects due to the length of the car.) dx 30 m 20 m Building A Building B 75 m l 25 m 50 mExplanation / Answer
height difference=30-20=10 m
horizontal distance to be covered=25 m
let required speed at the edge of the building A is v m/s.
initial vertical speed=0
vertical acceleration=9.8 m/s^2
distance to be covered vertically=10 m
if time taken is t,
then 10=0*t+0.5*9.8*t^2
==>t=1.42857 seconds
horizontal distance to be covered=25 m
as horizontal acceleration in air is 0,
v=distance/time=25/1.42857=17.5 m/s
Q2.
initial speed when car starts=0
final speed at the edge of the building =17.5 m/s
acceleration=3 m/s^2
then distance=(final speed^2-initial speed^2)/(2*acceleration)
=51.0417 m
so he should start 51.0417 m from the edge of building A.
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