Two conducting spheres with diameters of 0.250 m and 1.00 m are separated by a d

Question

Two conducting spheres with diameters of 0.250 m and 1.00 m are separated by a distance that is large compared with the diameters. The spheres are connected by a thin wire and are charged to 2.00 A mu C. How is this total charge shared between the spheres? (Ignore any charge on the wire.) charge on smaller sphere Your response differs from the correct answer by more than 100%. A mu C charge on larger sphere Your response differs from the correct answer by more than 10%. Double check your calculations. A mu C What is the potential of the system of spheres when the reference potential is taken to be V = 0 at r = infinity?

Explanation / Answer

(a)

given that total charge = 2*10^(-6) C

charge on sphere 1 + charge on sphere 2 = 2*10^(-6)

Q1 + Q2 = 2*10^(-6) .......eq1

conductors are connected by a thin wire

potential on sphere1= potential on sphere 2

k*Q1/R1 = k*Q2/R2

Q1 /0.25 = Q2 / 1

4*Q1 = Q2 ......eq2

by solbing eq1 and eq2

Q1 = 0.4*10^(-6) C

Q2 = 1.6*10^(-6) C

(b)

system potential ,either side of Q2

V = 9*10^9 *1.6*10^(-6) / 1

V = 14.4 kV

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