A cheetah is traveling across the African countryside, initially moving at a con

Question

A cheetah is traveling across the African countryside, initially moving at a constant velocity of 14 m/s. It sees a gazelle at t = 0 seconds and begins to accelerate in a straight line. At t = 4 0 seconds it has a velocity of 23 m/s and then continues to move at this constant velocity At t = 5.0 seconds, the cheetah is standing still, having knocked over the gazelle. What is the average acceleration of the cheetah from t = 0 to t = 4 0 seconds? What is the average acceleration of the cheetah from t = 0 to t = 5.0 seconds?

Explanation / Answer

a)

Acceleration = change in velocity / time taken

So, from t = 0 to t = 4 seconds,

the average acceleration = (23 - 14) / 4 = 9/4 = 2.25 m/s^2

b)

average acceleration over 5 seconds = (23 - 14) / 5 = 9/5 = 1.8 m/s^2

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