When a lead-acid battery is discharged. H^+ ions (charge per ion = +1.6 times 10

Question

When a lead-acid battery is discharged. H^+ ions (charge per ion = +1.6 times 10^-19 C) are produced at the electrode on the left. These ions travel to the right and then are consumed by the electrode on the right. HS0_4^- ions (charge per ion = -1.6 times 10^-19 C) are originally inside the solution and consumed by both electrodes at the same rate. In 1 second, the net number of H^+ ions moving from left to right is 2 times 10^19. At the same time. 1 times 10^19 HSO_4^- ions is attached to the electrode on the left and 1 times 10^19 HSO_4^- ions is attached to the electrode on the right. What is the net current inside the cell and what is the direction of the current? A. 0 A B. 1.6 A (pointing to the right) C. 3.2 A (pointing to the left) D. 3.2 A (pointing to the right) D. 6.4 A (pointing to the right)

Explanation / Answer

We know that

The net current flowing through the cell is

inet =q/t

=ne/t

= (2*1019-1*1019)*1.6*10-19C/1sec

=1.6A pointing towards the right

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.