A block of mass m is on top of a block of mass M = 5 m . The two blocks are conn
ID: 1534918 • Letter: A
Question
A block of mass m is on top of a block of mass M = 5m. The two blocks are connected by a string that passes over an ideal pulley. The bottom block is also tied to a string - exerting a force F, after the blocks have been set in motion, causes the blocks to move at constant velocity.
Use g = 10 N/kg for this problem. The coefficient of kinetic friction between all surfaces in contact is 0.500.
A block of mass m is on top of a block of mass M 5m. The two blocks are connected by a string that passes over an ideal pulley. The bottom block is also tied to a string exerting a force F, after the blocks have been set in motion, causes the blocks to move at constant velocity. Use g 10 N/kg for this problem. The coefficient of kinetic friction between all surfaces in contact is 0.500. 2 3 5- a) For this scenario, which free-body diagrams (see above) are correct? Select the two correct diagrams, one for each block, and make sure you can identify which force is which. O The correct free-body diagram of the larger block is number 1. O The correct free-body diagram of the larger block is number 2. O The correct free-body diagram of the larger block is number 3. O The correct free-body diagram of the smaller block is number 4. O The correct free-body diagram of the smaller block is number 5. O The correct free-body diagram of the smaller block is number 6. (b) If the value of m is 260 g, what is the value of F?Explanation / Answer
a) the correct free-body diagram of the larger block is number 2 and of the smaller block is number 4
equation of motion of m
F - T - k * (M + m) * g + k * m * g = Ma
since the block moves with constant velocity so acceleration will be 0 m/s^2
F - T - 0.5 * (5 * 0.26 + 0.26) * 10 + 0.5 * 0.26 * 10 = 0 --------------(1)
equation of motion of m
T - k * m * g = ma
T - 0.5 * 0.26 * 10 = 0 ---------(2)
on solving equation 1 and 2 we'll get
b) F = 7.8 N
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