A cylindrical space-station with a diameter of 500 [m] maintains Earth-like arti

Question

A cylindrical space-station with a diameter of 500 [m] maintains Earth-like artificial gravity for its inhabitants walking on its inner surface by rotating on its longitudinal axis. Find the time it takes to make one complete revolution. A person on an elevator inside the station has a mass of 100 [Ag]. Assume the elevator "hangs" from a pivot so that it can maintain the feeling inside that "down" points toward the floor of the elevator. if the elevator is accelerating up toward the axis of the station (relative to the station) at 3 [m/s^2], find his apparent weight at the instant that the velocity of the elevator (relative to the station) is 1 [m/s] and his radial distance from the axis of rotation is 400 [m] find the angle between the "down" direction in the elevator and the radial direction relative to the axis of the space station.

Explanation / Answer

only could able to do a)

Centripetal acceleration: a = v²r, so v = (a·r). Here, a = g = 9.8 m/s² and r = 500 m

so, v = ((9.8 m/s²)(500 m)) = 70 m/s

Circumference: C = 2r = 2(500 m) = 1000 = 3142 m (approx.)
so, time to take one complete revolution = (3142 m)/(70 m/s) = 44.9 s (approx.),

or, we can do it another way

time period = 2pi sqrt(r/g) = 2x3.14 sqrt(500/9.8) = 44.857 s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.