A cylindrical container with a diameter of 7.62 cm is resting on the bottom of y

Question

A cylindrical container with a diameter of 7.62 cm is resting on the bottom of your friend's swimming pool in the orientation shown in the figure. The swimming pool is 9.14 m deep. The density of the chlorinated water in the swimming pool is 1.15x10^3 kg/m^3.

a) What is the magnitude of the force that the water is exerting on a circular side of the cylinder?

b) The cylinder's weight in air, before it was dropped into the pool, was 22.2 N. It's weight at the bottom of the swimming pool is 14.0 N. What is the horizontal length of the cylinder, in cm?

Explanation / Answer

Part A)

P = pgh = F/A

(1150)(9.8)(9.14) = (F)/(pi)(.0381)^2

F = 469.8 N

Part B)
Fb = Vpg

22.2 - 14 = (pi)(.0381)^2(l)(1150)(9.8)

l = .160 m (16.0 cm)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.