12:24 PM iPad 22% ust49wa.theexpertta.com Home I Student: Megan Montgomery@wsu.e

Question

12:24 PM iPad 22% ust49wa.theexpertta.com Home I Student: Megan Montgomery@wsu.edu My Account Log out Class Management I Help Homework #4: optical Devices Begin Date: 2/17/2017 1:59:00 PM Due Date: 2/23/2017 11:59:00 PM End Date: 5/8/2017 11:59:00 PM (13%) Problem 2 young woman with normal distant vision (that is, a focal length of 2.00 cm) has a 8.5% ability to accommodate (that is, increase) the power of her eyes Randomized Variables AP/P(%) 8.5 A How close, in centimeters, is the closest object she can see clearly? Grade Summary Deductions 0% Potential 100% Submissions 7 8 9 sin cos Attempts remaining: 20 cotan0 asin acos() 4 5 6 per attempt atan() acotano sinh() 1 2 3 detailed view cosh() tanh cotanh0 Degrees O Radians Hint Submit I give up! Hints 0% deduction per hint. Hints remaining 3 Feedback: 0% deduction per feedback. All content 2017 Expert TA, LLC

Explanation / Answer

Power for normal distant vision = 50 D

Hre max power = 54.25 D

P = 1/do + 1/di

1/d0 = P - 1/di = ( 54.25 - 50 )

1/do= 4.25

do = 23.529 cm apprx

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