An astronaut on a distant planet wants to determine its acceleration due to grav

Question

An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of + 16 m/s and measures a time of 15.4 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (Indicate direction by the sign of the acceleration.) A speed ramp at an airport is basically a large conveyor belt on which you can stand and be moved along. The belt of one ramp moves at a constant speed such that a person who stands still on it leaves the ramp 63 s after getting on. Clifford is in a real hurry however, and skips the speed ramp. Starting from rest with an acceleration of 0.30 m/s^2, he covers the same distance as the ramp does, but in one fourth the time. What is the speed at which the belt of the ramp is moving?

Explanation / Answer

y = v0 t + 1/2 a t2

a = - v0 t / 1/2 t2

a = - 2 v0 / t = (-2 * 16) / (15.4)

= -2.08 m/s2

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