An electron and a proton are separated by a distance of 1.7 times 10^-10 m (roug

Question

An electron and a proton are separated by a distance of 1.7 times 10^-10 m (roughly the diameter of a single atom). What is the magnitude of the electric interaction between the electron and the proton? magnitude of electric force = What is the magnitude of the gravitational interaction between the electron and the proton? magnitude of gravitational force = In this scenario, how many times stronger is the electric force than the gravitational force? The electric force is times stronger than the gravitational force.

Explanation / Answer

let q1 and q2 be the charges of electron and proton respectievly

q1 = -1.6*10^-19 C and q2 = 1.6*10^-19 C

and m1 and m2 be the masses of electron and proton respectievly

m1 = 9.11*10^-31 Kg

m2 = 1.67*106-27 Kg

magnitude of electric force is Fe = k*q1*q2/r^2 = (9*10^9*(1.6*10^-19)^2)/(1.7*10^-10)^2 = 7.97*10^-9 N

magnitude of gravitational force is Fg = G*m1*m2/r^2 = (6.67*10^-11*9.11*10^-31*1.67*10^-27)/(1.7*10^-10)^2 = 3.511*10^-48 N

Fe/Fg = (7.97*10^-9)/(3.511*10^-48)

Fe/Fg = 2.27*10^39

Fe = 2.27*10^39*Fg

the electric force is 2.27*10^39 times stronger than the gravitational force

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