When a large hone such as the femur is broken, the two pieces are often pulled o

Question

When a large hone such as the femur is broken, the two pieces are often pulled out of alignment by the complicated combination of tension and compression forces that arise from the muscles and tendons In the leg (see the X-ray image in Figure P3.64A). To realign the hones and allow proper healing, these forces must be compensated for. A method called traction is often employed. A total tension force of 550 N is applied to the leg as depicted in Figure P3.64B to realign the parts of the femur. How does the tension in the "pulley rope" (lire one that is attached to the ceiling, winds through 3 pulleys, and is attached to tire mass) relate to the mass? What is the tension of the rope attached to the mass? It will help lo think about tire horizontal forces on the "middle' (left-most) pulley. How much mass, m, must be attached to the bottom pulley?

Explanation / Answer

The tension of the rope attched to the mass is

Fy = T- mg= 0

T= mg

T = 28.06(9.8)

=275 N

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