Two particles which have the same magnitude charge but opposite sign are held 8.

Question

Two particles which have the same magnitude charge but opposite sign are held 8.00 nm apart. Particle I is then released while Particle II is held steady; the released particle has a mass of 7.03 times 10^-23 kg. Particle I's speed is 72.0 km/s when it is 6.64 nm away from Particle II. What is the magnitude of the charge on one of the particles? _________________ C If the particles are still initially held 8.00 nm apart but both particles are released, when they are 6.64 nm away from each other, how would Particle I's speed compare to the speed used in part (a) above? (Assume that Particle II's mass is not the same as Particle I's; you should be able to answer this without performing a detailed calculation.)

Explanation / Answer

the charge is calculated as follows:

kq^2(1/r2 - 1/r1) = 0.5 m v^2

9e9*q2 (1/6.64e-9 - 1/8e-9) = 0.5*7.03e-23*[72e3]2

hence, the charge is,

q = 8.89x10-16 C

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