The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a =
ID: 1540141 • Letter: T
Question
The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.0 V and b = -6.50V/m. Determine the potential at x = 0. _____ V Determine the potential at x = 3.00 m. ______ V Determine the potential at x = 6.000 m. ______ V Determine the magnitude and direction of the electric field at x = 0. magnitude ______ V/m direction Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude ______ V/m direction Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude ______ V/m directionExplanation / Answer
v = a + bx
at x = 0
v = 15 + (-6.5)*0 = 15 V
at x = 3
v = 15 - 19.5 = -4.5 V
at x = 6
v = 15 - 39 = -24 V
magnitude and direction of electric field at x = 0
E = -6.5 V/m
at x = 3
E = 15/3 - 6.5 = -1.5 V/m
at x = 6
E = 15/6 - 6.5 = -4 V/m towards the origin
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