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The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a =

ID: 1540141 • Letter: T

Question

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.0 V and b = -6.50V/m. Determine the potential at x = 0. _____ V Determine the potential at x = 3.00 m. ______ V Determine the potential at x = 6.000 m. ______ V Determine the magnitude and direction of the electric field at x = 0. magnitude ______ V/m direction Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude ______ V/m direction Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude ______ V/m direction

Explanation / Answer

v = a + bx

at x = 0

v = 15 + (-6.5)*0 = 15 V

at x = 3

v = 15 - 19.5 = -4.5 V

at x = 6

v = 15 - 39 = -24 V

magnitude and direction of electric field at x = 0

E = -6.5 V/m

at x = 3

E = 15/3 - 6.5 = -1.5 V/m

at x = 6

E = 15/6 - 6.5 = -4 V/m towards the origin

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