A simple and common technique for accelerant electrons is shown in the figure, w

Question

A simple and common technique for accelerant electrons is shown in the figure, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. A Calculate the horizontal component of the acceleration of the electron if the field strength is 2.4 times 10^4 N/C. Express your answer in ms', and assume the electric field is pointing m the negative. v-direction as shown in die figure.

Explanation / Answer

Given

Electric field E = 2.4*10^4 N/C

mass of electron m = 9.1093*10^-31 kg

charge of electron q = -1.6*10^-19 C

now F = E*q

F = ma

   Eq = ma

   ax = Eq/m

   ax = 2.4*10^4*1.6*10^-19 / (9.1093*10^-31)

   ax = 4.2154721*10^15 m/s2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.