A silver block, initially at 56.6 C, is submerged into 100.0 g of water at 25.0

Question

A silver block, initially at 56.6 C, is submerged into 100.0 g of water at 25.0 C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.5 C.

Part A

What is the mass of the silver block?

Express your answer to two significant figures and include the appropriate units.

A silver block, initially at 56.6 C, is submerged into 100.0 g of water at 25.0 C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.5 C.

Part A

What is the mass of the silver block?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

A silver block, initially at 56.6 C, is submerged into 100.0 g of water at 25.0 C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.5 C.

Qsilver = m1*C1*(Tf-T1)

Qwater = m2*c2*(Tf-T2)

Qsilver = -Qwater

so

m1*C1*(Tf-T1)= -m2*c2*(Tf-T2)

m1*0.233*(27.5-56.6) = -100*4.184*(27.5-25)

m1 =  -100*4.184*(27.5-25) / (0.233*(27.5-56.6)) = 154.2704 g of silver

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