A 2-mu F and a 1 - mu F capacitor arc connected in series and a potential differ

Question

A 2-mu F and a 1 - mu F capacitor arc connected in series and a potential difference is applied across the combination. The 2-mu F capacitor has: twice the charge of the 1-mu F capacitor has: half the charge of the 1-mu F capacitor twice the potential difference of the 1-mu F capacitor half the potential difference of the 1-mu F capacitor none of the above The diagram shows six-mu F capacitors. The capacitance between points a and b is: 1 mu F 3 mu F 4 mu F 6 mu F 9 mu F A charged capacitor stores 10 C at 40 V. What is the value of its stored energy? 400 J 200 J 4 J 2.5 J 1.25 J

Explanation / Answer

11) (D)Half the potential difference of the 1 uF capacitor.

Because:

Let, C1 = 2 uF and C2 = 1 uF

Same charge flows through the capacitors connected in series

Q1 = Q2

V1/C1 = V2/C2

V1/2 = V2/1

V2 = V1/2

12)(C)

the upper three and lower three are in series and their combination is in parallel to each other.

1/C(upper) = 1/6 + 1/6 + 1/6 = 3/6 = 0.5

C(upper) = 2

C(lower) = 2

Ceq = C(upper) + C(lower) = 2 + 2 = 4

Ceq = 4 uF

13) (B)200 J

Q = 10C ; V = 40 V

U = 1/2 C V^2 = 1/2 Q V = 1/2 Q^2/C

U = 0.5 x 10 x 40 = 200 J

U = 200 J

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