Consider the 13.5-kg motorcycle wheel shown in the figure below. Assume it to be

Question

Consider the 13.5-kg motorcycle wheel shown in the figure below. Assume it to be approximately an annular ring with an inner radius of

R1 = 0.280 m

and an outer radius of

R2 = 0.480 m.

The motorcycle is on its center stand, so that the wheel can spin freely.

a) IF THE DRIVE CHAIN EXERTS A FORCE OF 2225 N at a radius of 5 cm what is the angular acceleration of the wheel?

b) what is the tangential acceleration of a point on the outer edge of the tire?

c) How long, starting from rest, does it take to reach the angular velocity of 80.0 rad/s

Explanation / Answer

  I = ½m*(R1²+R2²) = 2.08 kgm²

torque(T) = I

a) = T/I = 2225*0.05/2.08 = 53.48 rad/sec²

b) a = *R2 = 25.67 m/sec²

c) t = w/ = 80/8.898 = 1.495 sec

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