Calculate the Hall voltage Delta V_Hall for the case of a ribbon of copper 6 mm

Question

Calculate the Hall voltage Delta V_Hall for the case of a ribbon of copper 6 mm high and 0.3 m deep, carrying a current of 21 amperes in a magnetic field of 1 tesla For copper, q = -e, and n = 8.4 m times 10^28 free electrons per m^3 (one per atom). V This is a very small voltage, but it can be measured with a sensitive voltmeter. In semiconductors the density of charge carriers n may be quite small compared to a metal, in which case the Hall effect voltage can be quite large, since it is inversely proportional to n.

Explanation / Answer

V(H) = -iB / dnE
i = current
B = magnetic field
d = depth of plate
n = free electrons per m^3
e = charge

V(H) = -(21*1) / (0.3E-3 * 8.4E28 * 1.6E-19) = -0.52083E-5 V

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.