Calin Calin College 67 100 100 100 100 100 00 100 10 he Web and Mindows Print Ca

Question

Calin Calin College 67 100 100 100 100 100 00 100 10 he Web and Mindows Print Calculator Periodic Table Question 9 of 11 Map A Sapling Learning A simple pendulum with a period T- 5.00 s is attached to the ceiling of an elevator which is initially at rest. Calculate the period of osci ations when the elevator begins to accelerate upwards with acceleration a 0.50 m/s Number Calculate the period of oscil ations when the elevator accelerates d s with acceleration a 2.50 m/s2. Number 3.48 AD Previous Check Answer Next Exit Hint Ava Due Pool Grai Des Poli You You You The O H O W OTE

Explanation / Answer

T = 2[L/g] ------ (1) when the pendulum is at rest.

where T = time period of the pendulum, L = length of the pendulum, g = acceleration due to gravity

when the pendulum along with the elevator begins to accelerate upwards with an accelration a = 0.5m/s2, the time period of the pendulum becomes

T1 = 2[L/(g+a)] ------- (2)

from equation (1) and (2) we get

T1/T = [g/(g+a)]

or T1 = T[g/(g+a)]

or T1 = (5s)[10m/s2/(10m/s2 + 0.5m/s2)]

or T1 = 4.879s

When the pendulum along with the elevator begins to accelerate downwards with an accelration a = 2.5m/s2, the time period of the pendulum becomes

T2 = T[g/(g-a)]

or T2 = (5s)[10m/s2/(10m/s2 - 2.5m/s2)]

or T2 = 5.773s

This concludes the answers. Check the answer and let me know. I will resolve your query without delay.....

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