A typical jogger burns up food energy at the rate of about 43 kJ per minute. How

Question

A typical jogger burns up food energy at the rate of about 43 kJ per minute. How long would it take to run off a piece of cake if it contains 450 Calories? ______________ min 70 grams of water at 75 degree C are mixed with an equal amount of water at 25 degree C in a completely insulated container. The final temperature of the water is 50 degree C. (a) How much heat is lost by the hot water? _____________ cal (magnitude only) (b) How much heat is gained by the cold water? ____________ cal (magnitude only) (c) What happens to the total amount of internal energy of the system? doubles halves remains unchanged

Explanation / Answer

43000/60 kJ / min = 716.67 J / s

450 cal = 1.883e+6 J

time = 1.883e+6 /716.67 = 2627.43 s = 43.79 mins

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