A homeowner is trying to move a stubborn rock from his yard which has a mass of

Question

A homeowner is trying to move a stubborn rock from his yard which has a mass of 525 kg. By using a lever arm (a piece of metal rod) and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum d = 0.211 m from the rock so that one end of the rod fits under the rock's center of weight. If the homeowner can apply a maximum force of 647 N at the other end of the rod, what is the minimum total length L of the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. L = m

Explanation / Answer

torque on fulcurm

F*d

F = mg

d = 0.211m

and torque on other side of fulcurm

647*x

525 * 9.8 *0.211 = 647 *x

x = 1.68 m

L = d+x = 1.891 m = 1.9 m

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