A uniform meter sick of mass 140 g is held horizontally by two vertical string o

Question

A uniform meter sick of mass 140 g is held horizontally by two vertical string one at the zero cm mark and the other at the 92 cm mark. Find the tension the string at the 92 cm mark. A small 700 g ball on the end of a thin, light rod is rotated in a horizontal of radius 2.0 m. Calculate the torque needed to keep the ball rotating at a constant angular speed if the air resistance experienced by the ball is 0.1 N. Ignore the rods moment of inertia and air resistance. A combination of an applied force and a frictional force produce a constant total torque of 32 N-m on a wheel rotating about a fixed axis. This combine force acts for 7 s, during which the wheel's angular speed increases from 0.20 rad/s. Find the moment of inertia of the wheel.

Explanation / Answer

let,

mass of the meter stick is , m=140 g

tension at x1=0cm is T1

tension at x2=92cm is T2

at equilibrium,

net torque =0

T1*x1+m*g*l/2 -T2*(l-x2)=0

0+140*10^-3*9.8*0.5-T2*(1-0.92)=0

===> T2=8.57 N

tension, T2=8.57 N

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