Calculate the rotational Inertia (kg*m^2) of a wheel that has a kinetic energy o

Question

Calculate the rotational Inertia (kg*m^2) of a wheel that has a kinetic energy of 28400 J when rotating at 552 rpm. (in kg*m cap 2) 5.58 8.08 1.17 times 10^1 1.70 times 10^1 2.46 times 10^1 3.57 times 10^1 5.18 times 10^1 7.51 times 10^1 1.09 times 10^2 1.58 times 10^2 What must the separation be between a 6.1 kg particle and a 4.0 kg particle in order for their gravitational attraction to be 2.357 times 1-^-11 N? (in m) 8.31 1.20 times 10^1 1.75 times 10^1 2.53 times 10^1 3.67 times 10^1 5.33 times 10^1 7.72 times 10^1 1.12 times 10^2 1.62 times 10^2 2.35 times 10^2

Explanation / Answer

46. K.E. = (1/2)* I * w2

I = 2* 28400 / (552 * 2/60)2 = 17

Answer is option D

47. F = GMm/r2

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