Calculate the r.m.s motor power for the following balanced cylindrical drum wind

Question

Calculate the r.m.s motor power for the following balanced cylindrical drum winder fitted with an equal mass tail rope and driven by a directly coupled electric motor. Mass of mineral hoisted per wind, 1-785 t; mass of each empty cage and wagons, 2-68 t; shaft depth, 640 m; height top cage position to headgear pulley, 27-5 m, distance headgear pulley to winding drum, 46 m, rope loop below bottom cage position, 15 m; winding drum diameter, 3-75 m, moment of inertia of all rotating parts, including rope on drum, 95 t m^2; friction torque, 12 kN m; rope mass 4-45 kg/m, acceleration time, 15 s, constant speed time, 55 s, retardation time, 15 s, loading and unloading time per cycle, 15 s. A twin skip, drum winding installation is to raise 510 mph (t/hr.) at a depth of 500 m. The decking time is 12 s. The mass of each skip and its suspension gear equals 90% of the payload raised. Draw a conceptual sketch of the hoisting. Design the kinematics (maximum speed, acceleration, retardation, etc.) Determine the payload capacity of each skip. Determine the rope and drum size. Find the RMS rating and the power of the motor.

Explanation / Answer

Answer to the first question :

on calculation , rms value on basis of given data is 78.

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