Calculate the potential for each cell as shown below and indicate whether the me

Question

Calculate the potential for each cell as shown below and indicate whether the metal electrode in the half reaction opposite the standard hydrogen electrode, S.H.E., would be the anode or the cathode if the cell was shorted and electrons were allowed to flow freely at 25 C. A) S.H.E. II Zn 2+ (aq, 0.0480 M) Zn(s) ED Zn Izne 0.762 V The Zn electrode is the Number O anode O cathode 0.76 ce B) Pt(s) IV9 (aq, 0.240 M), V2 (aq, 0.00880 M) lls. H. E. Eo 3+ 0.255 v The Pt electrode is the Number o anode cell 0.255 O cathode Incorrect.

Explanation / Answer

(A)

Cell reaction:

Zn (s) + 2 H+ (aq.) (1.00 M) ------------> Zn2+ (0.0480, aq.) + H2 (g)

Applying Nernst equation,

Ecell = E0cell - (0.05916 / n ) Log[Zn2+]/[H+]2

Ecell = - 0.762 - (0.05916/2)*Log(0.0480)

Ecell = - 0.723 V

PART (B)
Cell reaction can be written as,

2 V2+ (0.00880M,aq.) + 2H+ (1.00M,aq.) -------------> 2 V3+ (0.240Maq.) + H2 (g)

Applying Nernst equation,

Ecell = E0cell - (0.05916/n)*Log[V3+]2/[V2+]2[H+]2

Ecell = - 0.255 - (0.05916 / 2) * Log(0.240)2 / (0.00880)2

Ecell = - 0.340 V

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