Calculate the potential for each cell as shown below and indicate whether the me

Question

Calculate the potential for each cell as shown below and indicate whether the metal electrode in the half- reaction opposite the standard hydrogen electrode, S.H.E., would be the anode or the cathode if the cell was shorted and electrons were allowed to flow freely at 25 . A) S.H.E. II Zn2(aq, 0.0340 M) | Zn(s) E .762 v e Zn electrode is the Number O anode Ecel 80 Incorrect. You have reversed the right and left half-cells in your calculation of the overall cell potential. For this cell, Zn2 Zn is the right half-cell and S.H.E. is the left half-cell. Recall that Ecell Enight- Eieft cathode B) Pt(s) | V& (aq, 0.295 M), V2(aq, 0.00720 M)II S.H.E ,, , ,.--0.255 V he Pt electrode is the Number O anode. O cathode

Explanation / Answer

Answer:

A) For this cell

Anode : H2 2H+ + 2e- 0.0V

cathode: Zn2+ + 2e- Zn -0.762 V

ECell = Eocathode - Eoanode

= (-0.762) - 0.0

ECell =-0.762V

B) for this cell

Anode : H2 2H+ + 2e- 0.0V

cathode: V3+ + e-n V2+ -0.255V

ECell = Eocathode - Eoanode

= (-0.255) - 0.0

   ECell =-0.255V

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