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a Secure | https://session.masteringphysics.com/myct/itemView?assignmentProblemlD-91077342 Find the magnitude of E in the membrane between the two layers of charge Some cell membranes in the human body have a layer of negative charge on the inside surface and a layer of positive charge of equal magnitude on the outside surface. Suppose that th density on either surface is ± 0.50 × 10-3 C/m2, the cell membrane is 5.00 nm thick, and the cell membrane is made up of tissue with a dielectric constant of 5.40 e charge Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Part B Find the potential difference between the inside and the outside of the cell. Which is at the higher potential? Submit Previous Answers Request Answer

Explanation / Answer

a)

Electric field is given by

E=sigma/eo=0.5*10-3/(8.8542*10-12)=5.647*107 V/m

b)

Potential differene

V=Ed=(5.647*107)*(5*10-9)=0.02824 Volts

c)

volume of the cell

V=(4/3)piR3=10-16

R=2.88*10-6 m3

Volume of the wall

V=4piR2d =4pi*(2.88*10-6)2*(5*10-9)=5.21*10-19 m3

The total electric field energy is

U=(1/2)eoE2V =(1/2)*(8.8542*10-12)*(5.647*107)2*(5.21*10-19)

U=7.354*10-15 J

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