The circuit in the diagram consists of a battery with EMF E, a resistor with res

Question

The circuit in the diagram consists of a battery with EMF E, a resistor with resistance R, an ammeter, and a voltmeter. The voltmeter and the ammeter (labeled V and A, respectively) can be considered ideal; that is, their resistances are infinity and zero, respectively. The current in the resistor is I, and the voltage across it is V. The internal resistance of the battery rint is not zero

What is the ammeter reading I?

Express your answer in terms of E, R, and rint.

What is the voltmeter reading V?

Express your answer in terms of E, R, and rint.

n the following parts, you will express the power dissipated in the resistor of resistance R using three different sets of variables.

What is the power PR dissipated in the resistor?

Express your answer in terms of I and V.

Again, what is the power PR dissipated in the resistor?

This time, express your answer in terms of one or more of the following variables: I, rint, and R.

For the third time, what is the power PR dissipated in the resistor?

Express your answer in terms of one or more of the following variables: E, rint, and R

Explanation / Answer

Solution:

1) Ammeter reads the current in the circuit. It is calculated using the Ohm's law I =E/ (R+rint) .

2) V = I * R = (E/(R+r int) * R  

= E R /(R+rint) .

3) Power is defined as the rate of energy flow.

P = V I  

4) Power = V I =[ E/(R+rint)]* I .

5) The value of V and I can be taken from the above equations.

= [E * R / (R+rint) ] (E / (R+rint) = [(E)2 /(R+rint)2] R .

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