he experiment you will make a very fundamental measurement the ratio of the char
ID: 1580311 • Letter: H
Question
he experiment you will make a very fundamental measurement the ratio of the charge of the electron can find the charge-to-mass ratio. 1. What is the equation that gives the charge-to-mass ratio in terms of v, B, and r? In t to its mass. To do that you will use a magnetic field to cause electrons to follow a circular path. If you know v, the s no wwi te ed f the electrons, B, the magnitude of teld, and r, the radius of the eirecular piath, you 2. The electrons in the lab are accelerated through a potential difference that you control. What is the Hint: consider conservation of energy n electron that is released from rest and accelerated through a potential difference of 100 volts? 3. A larger potential difference corresponds to a higher speed. By what factor should you multiply the potential difference to double the speed of the electrons?Explanation / Answer
1.
Centripetal force is balanced by magnetic force
mv2/r =qvB
=>q/m =v/rB
2.
By Conservation of energy
(1/2)mv2=qV
(1/2)*(9.11*10-31)*v2=(1.602*10-19)*100
v=5.93*106 m/s
3.
By Conservation of energy
(1/2)mv2=qV
V=(1/2)(m/q)v2
=>V2/V1=(v2/v1)2
V2/V1 =22=4
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