Chapter 27, Problem 045 In the figure the resistances are R1 = 1.2 and R2 = 2.4

Question

Chapter 27, Problem 045 In the figure the resistances are R1 = 1.2 and R2 = 2.4 , and the ideal batteries have emfs ,-2.0 v, and 2 = 3- 5.9 V. What are the (a) size and (b) direction (up or down) of the current in battery 1, the (c) size and (d) direction of the current in battery 2, and the (e) size and (f) direction of the current in battery 3? (9) What is the potential difference Va - Vb? Ri Ry (a) Number Units (c) Number Units (e) Number Units (g) Number Units Click if you would like to Show Work for this question: Open Show Work

Explanation / Answer

let I1(downward), I2(upward) and I3(upward) are the currents through the batteries e1,e2 and e3 respectively.

at the junction, I1 = I2 + I3 ----(1)

Apply KVL IN left loop

5.9 - 2.4*I2 - 1.2*I1 - 2 - 1.2*I1 = 0 ----(2)

Apply KVL in right loop

5.9 - 1.2*I3 + 2.4*I2 - 5.9 - 1.2*I3 = 0 ---(3)

on solving the above equations we get
I1 = 1.08
I2 = 0.54
I3 = 0.54

a) 1.08 A
b)down
c) 0.54 A
d)up
e) 0.54 A
f) up
g) Vb + 2 - 2.4*0.54 = Va

Va - Vb = 2 - 2.4*0.54

= 0.704 V

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.