You may want to review (Pages 778 - 783) . Part A What is the speed of the deute

Question

You may want to review (Pages 778 - 783) .

Part A

What is the speed of the deuterons when they exit?

Express your answer with the appropriate units.

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Part B

If the magnetic field inside the cyclotron is 1.25 T, what is the diameter of the deuterons' largest orbit, just before they exit?

Express your answer with the appropriate units.

SubmitRequest Answer

Part C

If the beam current is 430 A how many deuterons strike the target each second?

A cyclotron is used to produce a beam of high-energy deuterons that then collide with a target to produce radioactive isotopes for a medical procedure. Deuterons are nuclei of deuterium, an isotope of hydrogen, consisting of one neutron and one proton, with total mass 3.34×1027kg. The deuterons exit the cyclotron with a kinetic energy of 6.10 MeV .

You may want to review (Pages 778 - 783) .

Part A

What is the speed of the deuterons when they exit?

Express your answer with the appropriate units.

v =

SubmitRequest Answer

Part B

If the magnetic field inside the cyclotron is 1.25 T, what is the diameter of the deuterons' largest orbit, just before they exit?

Express your answer with the appropriate units.

d =

SubmitRequest Answer

Part C

If the beam current is 430 A how many deuterons strike the target each second?

Q = deuetrons

Explanation / Answer

A) Given that KE = 0.5*m*v^2 = 6.1*10^6*1.6*10^-19 = 9.76*10^-13 J

0.5*3.34*10^-27*v^2 = 9.76*10^-13

v = 2.42*10^7 m/s

B) radius is r = (m*v)/(q*B) = (3.34*10^-27*2.42*10^7)/(1.6*10^-19*1.25)

r = 0.404 m
diameter is d = 2*r = 2*0.404 = 0.808 = 0.81 m

C) i = q/t

q = i*t = 430*10^-6*1 = 430*10^-6 C

no.of dueterons are n = (430*10^-6)/(1.6*10^-19) = 2.6875*10^15

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