In the figure, a horizontal force ModifyingAbove Upper F With right-arrow Subscr

Question

In the figure, a horizontal force ModifyingAbove Upper F With right-arrow Subscript a of magnitude 19.0 N is applied to a 2.96 kg book as the book slides a distance d = 0.97 m up a frictionless ramp at angle = 30°. (a) During the displacement, what is the net work done on the book by Upper F Overscript right-arrow EndScripts Subscript a, the gravitational force on the book, and the normal force on the book? (b) If the book has zero kinetic energy at the start of the displacement, what is its speed at the end of the displacement?

Explanation / Answer

part A:

WorkDOne by force Wf = Fd cos theta  

Wf = 19* 0.97 cos 30

Wf = 15.96 Joules

Work Done for gravitational force

Wg = -mgd cos theta

Wg = -2.96 * 9.81* 0.97 * cos 120

Wg = -14.08 Joules

Work Done by Normal Force

Wn = Nd cos theta 0 J

part B:

from Work enegry theroem

Wnet = delta K = Kf - Ki

15.96 - 14.08 + 0 = 0.5 * 2.96* (v^2-0^2)

v = 1.127 m/s

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