A squared loop of wire of side x\"10 cmis in a uniform magnetic field B=0.15 T.

Question

A squared loop of wire of side x"10 cmis in a uniform magnetic field B=0.15 T. What is the magnetic flux in the loop when: A. B is perpendicular to the face of the loop? B. B is at an angle 50 degress to the area of the loop? C. What is the magnitude of the average current in the loop if it has a resistance of 0.015 ohm and it is rotated from position a) to position b) in 0.15 s? A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and is steadily changing. Under these circumstances, an emf is induced in the coil. If the number of turns in the coil are now triplicated (but nothing else changes), what will be the induced emf in the coil? (Again, An answer not derived from a computation will not be valid. 2.

Explanation / Answer

1) we know, magnetic flux through a loop = A*B*cos(theta)

A is the area of the loop
B is the magnetic field
theta is the angle between normal to the loop and B

A) magnetic flux through the loop = A*B*cos(theta)

= 0.1^2*0.15*cos(0)

= 1.5*10^-3 T.m^2 or weber

B) magnetic flux through the loop = A*B*cos(theta)

= 0.1^2*0.15*cos(90-50)

= 1.15*10^-3 T.m^2 or weber

C)

induced emf = change in megntic flux/time taken

= (1.5 - 1.15)*10^-3/0.15

= 0.00233 V

induced current = induced emfR

= 0.00233/0.015

= 0.155 A

2) Induced emf becomes tripple.

because, induced emf is proportional to N

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