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Alternative Exercise 9.102 ) Consider the system shown in the figure (Figure 1).

ID: 1584584 • Letter: A

Question

Alternative Exercise 9.102 ) Consider the system shown in the figure (Figure 1). Assume that after the string breaks the ball falls through the liquid with constant speed, the mass of the bucket and the liquid is 1.60 kg, and the mass of the ball is 0.150 kg Part A Find the reading on the scale before the string breaks tD Submit Request Answer Part B Find the reading on the scale after the string breaks, assuming the ball falls through the liquid with arn acceleration equal to 0.260 g Figure 1 of 1> Submit Request Answer

Explanation / Answer

(A) before string breaks,

W = m g = (1.60 + 0.150) (9.8)

W = 17.15 N ....Ans

(B) on ball,

N - m g = m a

N = m a + m g = 0.150 (g + 0.260g) = 1.8522 N  


Reading, W = (1.60 x9.8) + 1.8522

W = 17.53 N .....Ans

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