Could someone please help me with this? Suppose the series resistors in the exam

Question

Could someone please help me with this?

Suppose the series resistors in the example are now 4.00 n and 2.00 n while the parallel resistors are 4.00 n (top) and 2.00 n (bottom and the battery provides an emf of 56.0 V (a) Find the equivalent resistance. Reg 6.67 How do resistors work together in series? How do they work together in parallel? n (b) Find the currents I, I and I 8.2963 I You used Ohm's law appropriately, but your value for the equivalent resistance was incorrect, making this answer wrong too. A 1.5555 What factors affect the current in a circuit? A What factors affect the current in a circuit? A

Explanation / Answer

a)
The equivalent of the parallel combination will be 4*2/(4+2) = 4/3 ohms
The equivalent of series combination will be
4+2 = 6 ohms.
So the equivalent resistance of the circuit will be
6+4/3 = 22/3 = 7.33 Ohms.
b)
The current I will be = voltage applied/ equivalent resistance = 56/7.33 = 7.636 A.
The ratio of currents I1 and I2 will be reverse of the ratio of resistances and I1+I2 = I = 7.636 A
So I1 = 7.636*2/(4+2) = 2.545 A
I2 = 5.09 A

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