An egg is thrown nearly vertically upward from a point near the cornice of a tal

Question

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point 48.3 m below its starting point 4.80 s after it leaves the thrower's hand. Air resistance may be ignored.

(a) What is the initial speed of the egg? m/s

(b) How high does it rise above its starting point? m

(c) What is the magnitude of its velocity at the highest point? m/s

(d) What are the magnitude and direction of its acceleration at the highest point? magnitude m/s2 direction

(e) Sketch a-t, v-t, and y-t graphs for the motion of the egg.

Explanation / Answer

a) Suppose the initial speed = u

then writting the equation of motion h = ut+0.5at^2

-48.3 = u*4.8 - 0.5*9.81*4.8^2

u = 13.48 m/s

b) maximum height = u^2/2g = 9.26 m.

c) At its height point the velocity will be zero.

d) The acceleration is constant throughout the motion.

Magnitude = 9.81 m/s^2

direction: vertically downwards.

e) a-t graph will be parallel to time axis

v-t will be straight line with a negative slope

y-t will be vertically downward parabola.

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