A uniform electric field of magnitude 387 V/m is directed in the positive x-dire
ID: 1589487 • Letter: A
Question
A uniform electric field of magnitude 387 V/m is directed in the positive x-direction. Suppose a 25 uC charge moves from the origin to point A at the coordinates, (40 cm, 53 cm). What is the absolute value of the change in potential from the origin to point A? Answer in units of V.
Let: Va is the potential at A and Vo is the potential of the origin. At which point is the electric potential larger?
1. Unable to determine
2. Vo > Va
3. Va > Vo
4. Va = Vo
What was the absolute of the change in potential energy from the origin to point A? Answer in units of J.
Let: Ua and Uo are the electric potential energies at point A and the origin, respectively. At which point is the potential energy larger?
1. Uo > Ua
2. Ua = Uo
3. undetermined
4. Ua > Uo
005 (part 1 of 4) 10.0 points A uniform electric field ofmagnitude 387 V/m is directed in the positive a-direction. Sup- pose a 25 C charge moves from the origin to point A at the coordinates, (40 cm, 53 cm) 387 V/m 40 cm, 53 cm) What is the absolute value of the change in potential from the origin to point A? Answer in units of V. 006 (part 2 of 4) 10.0 points Let: V is the potential at A and Vo is the potential of the origin. At which point is the electric potential larger? 1. Unable to determineExplanation / Answer
(1) Since the uniform electric field is along x-direction
so, absolute change in potential from origin to point A = E* x = 387V/m * 0.4m = 154.8 Volts
(2) Electric field lines originates from positive charge(higher potential) and ends to negative charge(lower potential).
Hence Vo > VA
(3) Absolute value of change in potential energy , U = chqrge * potential difference
= 25*10-6C * 154.8 V = 3.97*10-3 J
(4) Since potential at origin is larger than potential at A, hence potentail energy at O must be larger than the
potential energy at A. That is Uo >UA
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