A particle carrying charge + q is located on the x axis at x =+ d . A particle c

Question

A particle carrying charge +q is located on the xaxis at x=+d. A particle carrying charge -3q is located on the x axis at x=-7d.

A. With zero potential at infinity, at what location on the x axis with negative coordinate is the electrostatic potential zero? Express your answer in terms of d.

B. With zero potential at infinity, at what location on the x axis with positive coordinate is the electrostatic potential zero? Express your answer in terms of d.

C. At what location on the y axis with negative coordinate is the potential zero? Express your answer in terms of d.

D. At what location on the y axis with positive coordinate is the potential zero? Express your answer in terms of d.

E. Are there any locations on the x or y axis where the electrostatic potential is zero?

Explanation / Answer

k*q/(x-d) = k*3q/(7d+x)

1/(x-d) = 3/(7d+x)

x = 5d

+++++++++++

B)

k*q/(x+d) = k*3q/(7d-x)

1/(x+d) = 3/(7d-x)

x = -d

+++++++++

C)

k3q/sqrt(y^2+(7d)^2) = kq/sqrt(y^2+d^2)

3/sqrt(y^2+(7d)^2) = 1/sqrt(y^2+d^2)

9/(y^2+49d^2) = 1/(y^2+d^2)

9y^2 + 9d^2 = y^2 +49d^2

8y^2 = 40d^2

y = 5d

+++++++++++++

D)

k3q/sqrt(y^2+(7d)^2) = kq/sqrt(y^2+d^2)

3/sqrt(y^2+(7d)^2) = 1/sqrt(y^2+d^2)

9/(y^2+49d^2) = 1/(y^2+d^2)

9y^2 + 9d^2 = y^2 +49d^2

8y^2 = 40d^2

y = 5d

y = -5d

++++++++++++++++++

YES

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