A particle carrying charge + q is placed at the center of a thick-walled conduct
ID: 585905 • Letter: A
Question
A particle carrying charge +q is placed at the center of a thick-walled conducting shell that has inner radius R and outer radius 2R and carries charge 4q. A thin-walled conducting shell of radius 3R carries charge +4q and is concentric with the thick-walled shell. Define V = 0 at infinity.
Part A
Calculate all distances from the particle at which the electrostatic potential is zero.
Check all that apply.
Check all that apply.
A particle carrying charge +q is placed at the center of a thick-walled conducting shell that has inner radius R and outer radius 2R and carries charge 4q. A thin-walled conducting shell of radius 3R carries charge +4q and is concentric with the thick-walled shell. Define V = 0 at infinity.
Part A
Calculate all distances from the particle at which the electrostatic potential is zero.
Check all that apply.
Check all that apply.
r=5/6R r=11/5R r=9/4R r=6/7RExplanation / Answer
The electric field inside a conductor is zero.
Hence for R<r<2R the electric field will be zero.
Hence the induced charge on the inner surface of the thick walled shell will be -q and on the outer surface charge will be = -3q
a) at r = 5R/6 and r = 6R/7
V = kq/r-kq/R - 3kq/2R + 4kq/3R = kq/r - 7kq/6R
so at r = 6R/7 the potential will be zero.
b) at r = 11R/5 and r = 9R/4
V = -3kq/r + 4kq/3R = 0
r = 9R/4
hence at r = 9R/4 and R = 6R/7 the electric potential will,be zero.
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