You throw a 0.2 kg ball at a 47o angle with a speed of 35 m/s. Using an energy a

Question

You throw a 0.2 kg ball at a 47o angle with a speed of 35 m/s. Using an energy analysis find the maximum height the ball reaches relative to the release point. Don’t use the kinematic equations, they’re more work to use anyway.
You throw a 0.2 kg ball at a 47o angle with a speed of 35 m/s. Using an energy analysis find the maximum height the ball reaches relative to the release point. Don’t use the kinematic equations, they’re more work to use anyway.
You throw a 0.2 kg ball at a 47o angle with a speed of 35 m/s. Using an energy analysis find the maximum height the ball reaches relative to the release point. Don’t use the kinematic equations, they’re more work to use anyway.

Explanation / Answer

Here ,

for the maximum height

at the maximum height ,

v = 35 * cos(47) = 23.9 m/s

let the height is h

Using conservation of energy

0.50 * 0.20 * 35^2 = 0.50 * 0.20 * 23.9^2 + 9.8 * 0.20 * h

solving for h

h = 33.4 m

the height reached is 33.4 m

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