Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Print a Calculator Question 2 of 2 Sapling Learning learning Map Many physical p

ID: 1604252 • Letter: P

Question

Print a Calculator Question 2 of 2 Sapling Learning learning Map Many physical properties, such as force and mass, cannot be measured directly. Rather, some other physical property is measured and the desired physical property computed from the results. For example, a bathroom Scale does not actually measure mass or weight," but rather the compression distance of a spring. The such as on the are calibrated from the compression distance using basic physics principles Newton's second law. Coefficients of friction cannot be measured directly. In this problem, we are going to learn how we can indirectly measure the coefficient of kinetic friction between two surfaces by directly measuring the expansion spring. Consider a 2.12 kg block that is dragged by a spring on a (relatively) frictionless horizontal surface at constant velocity. Suppose the block reaches a rough patch and the spring stretches by 7.25 cm. Compute the coefficient of kinetic friction Ubetween the block and the rough patch if the spring has a force constant of 132.0 Nm. Number e Previous Check Answer e Next Exit

Explanation / Answer

friction force will be equal to spring force

f = k * x

where function is..

f= friction force,

k = spring constant

x = 7.25 cm = 0.0725 m(given)

now since f= ? * N

where function..

? = coefficient of kinetic friction

N = normal force = mg

hence f = ? * 2.12 * 9.8

putting above values in f = k* x

we get the function of

? = 0.0725 * 132 / (2.12 * 9.8)

? = 0.460

a.

In this the using

C = AEo/d

= 23.5*10^-4*8.85*10^-12/(7.20*10^-3)

= 2.88 pF

b.

Q = CV

= 2.88*10^-12*220

= 633.6 pC

electric field b/w the plates, E = V/d

= 220/(7.20*10^-3)

= 30.55*10^3 v/m

energy stored = Q/(2C)

= 633.6*10^-12/(2*2.88*10^-12)

= 110 J

c.

In this the ..acceleration of proton , a = qE/m

= 1.6*10^-19*30.55*10^3/(1.67*10^-27)

= 29.26*10^11 m/s^2

It is the final speed when reaches negative plate

v^2 = u^2 +2ad

v^2 = 0 + 2*29.26*10^11*7.20*10^-3

= 421.34*10^8

v = 4.21*10^6 m/s

that is tHe solve of the ...

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote