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An electron has been accelerated from rest through a potential difference of 800

ID: 1604967 • Letter: A

Question

An electron has been accelerated from rest through a potential difference of 800 V. You can think of this setup as placing an electron at rest at the negative plate of a parallel plate capacitor. If you release the electron, it will accelerate toward the positive plate. The potential difference is Vpos. plate - Vnet. plate.

a.) . What is the kinetic energy, in electron volts, of the electron as it reaches the positive plate?

b.)  What is its kinetic energy, in joules?

c.) What is its speed?

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Explanation / Answer

# Solution of part a

Here we would apply conservation of energy. When electron reaches the positive plate, all the Potential Energy (PE) gets converted into the Kinectic Energy (KE).

Hence KE= PE=qV=e800 or

KE= 800 eV. Ans.

# Solution of part b

We know that 1 eV= 1.6 * 10-19 J.

Hence 800 eV = 800*1.6*10-19 J =1280* 10-19 J Ans.

# Solution of part c

From part a we have KE= 800 eV = 1280*10-19 J

so 1/2mv2 = 1280*10-19 where m is mass of electron and v is its velocity

Note m=mass of electron is 9.1 * 10 -31 Kg

so v2 = 2*1280*10-19/m = 2560*10-19/9.1*10-31= 281.31*1012

So v = 16.77*106 m/s Ans

Please note, if we have to find the speed in m/s, we need to put all the values in SI unit i.e. for PE it would be in joule abd for mass m it would be in Kg.

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