Two toy cars are used to test both inelastic and elastic collisions. One car has
ID: 1607377 • Letter: T
Question
Two toy cars are used to test both inelastic and elastic collisions. One car has a mass m_1 = 1.0 kg, whereas the other car has a mass m_2 = 2.0 kg. The heavier car is initially at rest whereas the lighter car has an initial velocity v = 3.2 m/s as indicated in the sketch below a) Determine the final velocity of the system of both cars assuming they stick together after the collision with the help of a little magnet. b) Imagine another case that the mass mi bounces off elastically of mass m_2. Determine the velocity of each car after the collision. References: p = mv, K = 1/2 mv^2Explanation / Answer
(A)Applying momentum conservation,
1 x 3.2 = (2 + 1) vf
vf =1.07 m/s (both cars will move with this same velocity)
(B) for elastic collision,
velocity of approach = velocity of separation
3.2 = v1 + v2
v2 = 3.2 - v1
now Applying momentum conservation,
3.2 x 1 = 1(-v1) + 2v2
3.2 = - v1 + 2(3.2 - v1) = - v1 + 6.4 - 2v1
3.2 = - 3 v1 + 6.4
v1 = 1.07 m/s .....velociy of lighter car
v2 = 3.2 - 1.07 = 2.13 m/s ..........velccity of heavier car
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