An electron is projected with an initial speed 2.00*10^6 m/s into the uniform fi

Question

An electron is projected with an initial speed 2.00*10^6 m/s into the uniform field

figure is with image?

An electron is projected with an initial speed 2.00 times 10^6 m/s into the uniform field between the parallel plates in the figure (Figure 1). Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates. If the electron just misses the upper plate as it emerges from the field, find the speed of the electron as it emerges from the field?

Explanation / Answer

Force on electron = qE

a( accleration) = qE/ m

time ir remains in the electric field =( 2x 10^-3)/ (2x 10^6) = 10^-9 sec

vertical disatnce travelled(h) = (0.5 x 10^-2) = 1/2 ( a) ( 10^-9) ^2 = a ( 1/2x 10^-18)

final velocity = sqroot ( 2 a h ) = sqroot ( 2 a x a x 1/2 x 10^-18) = sqroot ( a^2 10^-18) = ax 10^-9 m/s

where, a= qE/m = 1.6 x 10^-19 ( E) / 9.1 x 10^-31 ) = 0.1758 x 10^ 12 E m/s^2

You need electric fikled to get the final valus. I have shown you the method

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