An electron is moving along the z-axis in the positive direction with a velocity
ID: 1357772 • Letter: A
Question
An electron is moving along the z-axis in the positive direction with a velocity of
6 × 107
m/s. If it is currently at the origin, answer the following questions.
a) What is the magnetic field at a distance of 30 m along the positive x-axis? Give both magnitude and direction.
Magnitdue: T
Direction: ---Select--- B = 0 +x -x +y -y +z -z
b) What is the magnetic force experienced by a proton located at this position? The proton has a velocity of
5 × 107
m/s.
Magnitude: N
Direction: ---Select--- F = 0 +x -x +y -y +z -z
c) What is the magnetic field at a distance of 30 m along the positive z-axis? Give both magnitude and direction.
Magnitdue: T
Direction: ---Select--- B = 0 +x -x +y -y +z -z
Explanation / Answer
1. formula for magnetic filed B = uo qv/4pi r^2 Biot Savart law
B = 4*3.14 e-7 * 1.6e -19 * 6 e7/(4*3.14*30e-6 * 30 e-6)
B = 1.06nT ., this is directed along negative y axis as evident from rgith hand rule
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2. magnetic force F = qVB
F = 1.6 e-19 * 5e 7 * 1.06 e -9
F = 8.48 e -21 N
-----------------------------------
along Z axis angle is 0 deg as sin 0 = 0
B = 0
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