The figure shows a light ray that is incident on a glass slab. Some of the light

Question

The figure shows a light ray that is incident on a glass slab. Some of the light is reflected, and some is transmitted into the slab. Determine the values of angles Theta_1 and Theta_2. The index of refraction for the glass is 1.43 Answer: (a) Theta_1 = 13.5 degree, and Theta_2 = 9.40 degree. (b) Theta_1 = 25.4 degree, and Theta_2 = 17.5 degree. (c) Theta_1 = 21.8 degree, and Theta_2 = 15.1 degree. (d) Theta_1 = 39.8 degree, and Theta_2 = 23.1 degree. (e) Theta_1 = 15.5 degree, and Theta_2 = 10.8 degree.

Explanation / Answer

from first law of reflection

incident angle = reflected angle

theta1 = 13.5 degrees

n1 =1, n2 = 1.43

from snells law

n1 sin(theta1) = n2sin(theta2)

1*sin(13.5) = 1.43*sin(theta2)

theta2 =9.4 degrees

correct option is (a)

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