A and B please A transverse wave on a string is given by the formula D(x, t) = 0

Question

A and B please

A transverse wave on a string is given by the formula D(x, t) = 0.20 sin (3.2x - 59.0t), where D and x are in m and t is in s. At t = 5.1 times 10^-2 s, what is the transverse displacement of the point on the string where x = 0.56m? Express your answer using two significant figures. D(0.56m, 5.1 times 10^-2s) = -0.004248 m At t = 5.1 times 10^-2 s, what is the (transverse) velocity of the point on the string where x = 0.56m? Indicate the direction of velocity with the sign of your answer. Express your answer using two significant figures. partial differential D/partial differential t (0.56m, 5.1 times 10^-2 s) = m/s

Explanation / Answer

Part (A)

Displacement y = 0.20sin(3.2*0.56 -59.0*(5.1/100)) = -0.004248 m

Part B

For Velocity

x = 0.20 sin(3.2x-59t)

velocity is the derivation of x w.r.t. time

v = -0.20*59 cos(3.2x-59.0t)

v = -0.20*59cos(3.20*.56 -59.0*(5.1/100)) = 0.250 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.