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Chrome File Edit View History Bookmarks People Window Help Mastering Physics: HW10 Secure https Sessio mastering physi cs.com/ next&assignment; ProblemID 77464264 c Do Physics 2200 New HW10 Problem 30.49 Mastering Ph Problem 30.49 My Courses Part A Course Home What would have to be the selfinductance of a solenoid for it to store 10.8 J of energy when a 1.40 A current runs through it? Syllabus Assignments Scores Course Tools Submit My Answers Give Up eText Part B Student Solu If this solenoid's cross-sectional diameter is 4.00 cm and if you could wrap its coils to a density of 10.0 coils/mm how long would the solenoid be? Manual Study Area User Settings Submit Hints My Answers Give Up Review Part Part C This question will be shown after you complete previous question (s). Learn more about assinnment sonres 78% Tue 1:18 AM Resources previous l 14 of 16 l next

Explanation / Answer

(a)

Energy stored in inductor

E = (1/2)*L*I^2

10.8 = (1/2)*L*(1.4)^2

L = 11.02 H

(b)

n = 10 coils/mm =10*10^3 coils/m

Area of solenoid

A = pi*d^2 / 4 = pi*(0.04)^2 / 4

A = 12.56*10^(-4) m^2

Inductance of a solenoid is

L = uo*n^2*A*l

11.02 = 4pi*10^(-7)*(10*10^3)^2*(12.56*10^(-4))*l

l = 69.85 m

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