Like we did in our resonance lab, a tuning fork is held above a tube with air in

Question

Like we did in our resonance lab, a tuning fork is held above a tube with air in it. The length of the air column is adjusted by raising or lowering the water level below it. This tube has a diameter of 3cm, and is found to resonate when the water is 15.5cm below the rim of the tube. Calculate the wave length of this resonance. From the temperature of the air in the column, we find the speed of sound to be 343 m/s. What is the frequency of this resonance? If the tuning fork is marked as 512 Hz, what is the relative error of our measured frequency?

Explanation / Answer

a)

at the open end antinode is formed

at the water surface node is formed

length of air column = distance between node and antinode

15.5 = wavelength/4

wavelength = 62 cm

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9)

frequency f = v/lambda = 343/0.62 = 553.22 Hz

10)

relative error = (553.22-512)/512 = 8.05 %

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