A beam of electrons are moving along the +x axis at a speed of 24 times 10^6 m/s

Question

A beam of electrons are moving along the +x axis at a speed of 24 times 10^6 m/s, when they enter a region of space that contains a uniform magnetic field of strength 0.033 T directed along the +y-axis. What is the magnetic force exerted on a single electron when it enters into the field? a. 1.30 times 10^- N b. 8.15 times 10^4 N c. 0.00 N d. 5.67 times 10^-14 N An object is placed inside the focal length of a converging thin lens. Which of the following will be true regarding the imaged formed by the lens? a. Image is real, inverted and smaller. b. Image is virtual, upright and larger, c. Image is real, upright and smaller. d. Image is virtual, inverted and larger. A Dean Markley 0.026-gauge acoustic guitar string has a tension breaking point of approximately 300 N and a linear mass density of 2.33 times 10^-3 kg/m. If the length of this string that is free to vibrate on the guitar is 1.00 m. What is the highest possible frequency sound that this string can produce without breaking? a. 360 Hz b. 180 Hz c. 146 Hz d. 196 Hz A speaker is outputting "Hakuna Mata" at a rate of 25 W. What is the intensity of the song when you are standing 15 m away from the speaker? a. 0.00 W/m^2 b. 0.13 W/m^2 c. 1.7 W/m^2 d. 0.0042 W/m^2 An object is placed in front of convex spherical mirror. Which of the following will be true regarding the image formed by the mirror? a. The image is real, upright and smaller. b The image is virtual, inverted and larger. c. The image is real, inverted and smaller. d. The image is virtual, upright and smaller. You wish to produce an image using a diverging lens with a focal length of 15 cm. If you want the image to be formed 11 cm away from the optical center, where should the object be placed along the principle axis? a. 22 cm b. 18 cm c. 41 cm d. 15 cm

Explanation / Answer

12. F=qvB = 1.6 x 10^-16 x 2.47 x 10^6 x 0.033 = option a)

13. Beyond the focal length, option b)

14. option b) using f= sqrt(T/ mu) / 2L

15. intenstiy = power / area = 25 / (4 x pi 15^2) option a)

16. option d)

17. 1/f = 1/v - 1/u , u = fv/ (f-v) = -15 x -11 / (-15 +11) = option c)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.